02202013, 05:26 PM
We'll be doing the same algebraically for the third. We want to understand everything about our values. (Price [x,y], what 5x and 4y equals, etc.)
5x + 4y = 32
x + 6y = 22
Solve for x to get an equation fit for substitution.
x = 22  6y
Plug it in.
5 (22  6y) + 4y = 32
Distribute the 5.
110  30y + 4y = 32
Subtract 110 on both sides and collect like terms.
26y = 78
Finish.
y = 3
We now know the price for 1 daisy because the problem says they are y dollars each.
Now, we'll find the price of the rose by plugging in our value and solve for x. You can use any given equation for this step.
x + 6(3) = 22
x + 18 = 22
Subtract 18.
x = 4
Plug your two values to test your values.
5(4) + 4(3) = 32?
20 + 12 = 32?
32 = 32 CORRECT
Seeing that one of your choices is "A rose costs $1 more than a daisy.", we can choose that answer immediately. We found that a rose was $4 each and a daisy is $3 each.
Last edited by Mr 223; 02202013 at 05:28 PM.
